3.3 Lösning 1d

\[\begin{array}{cccccrl} \displaystyle \frac{x}{2} & + & 11 & = & 14 & \quad & {\rm Täck\;över\;} \displaystyle \frac{x}{2} \\ \boxed{\displaystyle \frac{x}{2}} & + & 11 & = & 14 & & \\ \boxed{\;?\;} & + & 11 & = & 14 & & \\ \boxed{\;3\;} & + & 11 & = & 14 & & \end{array}\]

\[ \qquad \Downarrow \]

\[ \begin{array}{lcrcl} \;\displaystyle \frac{x}{2} & = & 3 & \quad & {\rm Täck\;över\;} x \\ \\ \displaystyle \frac{\boxed{x}}{2} & = & 3 & & \\ \\ \displaystyle \frac{\boxed{?}}{2} & = & 3 & & \\ \\ \;\displaystyle \frac{6}{2} & = & 3 & & \end{array}\]

\[ \qquad \Downarrow \]

\[ \;\;\; x \; = \; 6 \]