2.4 Lösning 3c
Från Mathonline
\[ y = 6 - 2\,\sqrt{x} \]
\[ y\,' = - 2\;{1 \over 2\,\sqrt{x}} = -{2 \over 2\,\sqrt{x}} = -{1 \over \sqrt{x}} \]
\[ y = 6 - 2\,\sqrt{x} \]
\[ y\,' = - 2\;{1 \over 2\,\sqrt{x}} = -{2 \over 2\,\sqrt{x}} = -{1 \over \sqrt{x}} \]