2.4 Lösning 2d
Från Mathonline
\( \displaystyle y = {4\,x^2 - 8\,x \over 5} = {4\,x^2 \over 5} - {8\,x \over 5} = {4 \over 5}\,x^2 - {8 \over 5}\,x \)
\( \displaystyle y\,' = 2\cdot {4 \over 5}\,x - {8 \over 5} = {8 \over 5}\,x - {8 \over 5} = {8 \over 5}\,(x - 1) \)
