1.7 Lösning 1a

$\displaystyle{{3\,^4 \cdot 3\,^2 \over 3\,^3} \; = \; {3\,^{4\,+\,2} \over 3\,^3} \; = \; {3\,^6 \over 3\,^3} \; = \; 3\,^{6\,-\,3} \, = \, 3\,^3 \, = \, 3 \cdot 3 \cdot 3 \, = \, 27}$