1.5 Lösning 1d
Från Mathonline
\[ {(x^{-2})^6 \cdot \sqrt{y} \over y^{0,5} \cdot (x^{-4})^3} = {x^{-12} \cdot \sqrt{y} \over y^{1 \over 2} \cdot (x^{-4})^3} = {x^{-12} \cdot y^{1 \over 2} \over y^{1 \over 2} \cdot (x^{-4})^3} = {x^{-12} \cdot y^{1 \over 2} \over y^{1 \over 2} \cdot x^{-12}} = 1 \]
