2.4 Lösning 4a

\( y = {x^2 + 3 \over x} = {x^2 \over x} + {3 \over x} = x + {3 \over x} = x + 3\cdot {1 \over x} \)

\( y\,' = 1 + 3\cdot -{1 \over x^2} \)