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		<title>3.2 Lösning 5a - Versionshistorik</title>
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		<updated>2026-04-26T12:08:54Z</updated>
		<subtitle>Versionshistorik för denna sida på wikin</subtitle>
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		<id>https://minidemo.mathonline.se/index.php?title=3.2_L%C3%B6sning_5a&amp;diff=19086&amp;oldid=prev</id>
		<title>Taifun: Skapade sidan med ':&lt;math&gt; f(x) = {x^4 \over 4} - 2\,x^2 &lt;/math&gt;  :&lt;math&gt; f\,'(x) = {4\,x^3 \over 4} - 4\,x = x^3 - 4\,x &lt;/math&gt;  :&lt;math&gt;\begin{array}{rcl}   x^3 - 4\,x &amp; = &amp; 0    \\...'</title>
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				<updated>2014-12-13T19:23:57Z</updated>
		
		<summary type="html">&lt;p&gt;Skapade sidan med &amp;#039;:&amp;lt;math&amp;gt; f(x) = {x^4 \over 4} - 2\,x^2 &amp;lt;/math&amp;gt;  :&amp;lt;math&amp;gt; f\,&amp;#039;(x) = {4\,x^3 \over 4} - 4\,x = x^3 - 4\,x &amp;lt;/math&amp;gt;  :&amp;lt;math&amp;gt;\begin{array}{rcl}   x^3 - 4\,x &amp;amp; = &amp;amp; 0    \\...&amp;#039;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;Ny sida&lt;/b&gt;&lt;/p&gt;&lt;div&gt;:&amp;lt;math&amp;gt; f(x) = {x^4 \over 4} - 2\,x^2 &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt; f\,'(x) = {4\,x^3 \over 4} - 4\,x = x^3 - 4\,x &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt;\begin{array}{rcl}   x^3 - 4\,x &amp;amp; = &amp;amp; 0    \\&lt;br /&gt;
                          x\,(x^2 - 4) &amp;amp; = &amp;amp; 0    \\&lt;br /&gt;
                                    x_1 &amp;amp; = &amp;amp; 0    \\&lt;br /&gt;
                               x^2 - 4 &amp;amp; = &amp;amp; 0    \\&lt;br /&gt;
                                    x^2 &amp;amp; = &amp;amp; 4   \\&lt;br /&gt;
                                    x_2 &amp;amp; = &amp;amp; 2    \\&lt;br /&gt;
                                    x_3 &amp;amp; = &amp;amp; -2   \\&lt;br /&gt;
       \end{array}&amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
Derivatan &amp;lt;math&amp;gt; \, f\,'(x) = x^3 - 4\,x \, &amp;lt;/math&amp;gt; har de tre nollställena:&lt;br /&gt;
&lt;br /&gt;
::::&amp;lt;math&amp;gt;\begin{array}{rcl} x_1 &amp;amp; = &amp;amp; 0    \\&lt;br /&gt;
                             x_2 &amp;amp; = &amp;amp; 2    \\&lt;br /&gt;
                             x_3 &amp;amp; = &amp;amp; -2   \\&lt;br /&gt;
          \end{array}&amp;lt;/math&amp;gt;&lt;/div&gt;</summary>
		<author><name>Taifun</name></author>	</entry>

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