<?xml version="1.0"?>
<?xml-stylesheet type="text/css" href="https://minidemo.mathonline.se/skins/common/feed.css?303"?>
<feed xmlns="http://www.w3.org/2005/Atom" xml:lang="sv">
		<id>https://minidemo.mathonline.se/index.php?action=history&amp;feed=atom&amp;title=1_1.2_L%C3%B6sning_5a</id>
		<title>1 1.2 Lösning 5a - Versionshistorik</title>
		<link rel="self" type="application/atom+xml" href="https://minidemo.mathonline.se/index.php?action=history&amp;feed=atom&amp;title=1_1.2_L%C3%B6sning_5a"/>
		<link rel="alternate" type="text/html" href="https://minidemo.mathonline.se/index.php?title=1_1.2_L%C3%B6sning_5a&amp;action=history"/>
		<updated>2026-04-21T08:11:42Z</updated>
		<subtitle>Versionshistorik för denna sida på wikin</subtitle>
		<generator>MediaWiki 1.23.1</generator>

	<entry>
		<id>https://minidemo.mathonline.se/index.php?title=1_1.2_L%C3%B6sning_5a&amp;diff=22896&amp;oldid=prev</id>
		<title>Taifun: Skapade sidan med ':&lt;math&gt; \, 3\,(6-4) + 2\,(5-2) = 3 \cdot (6-4) + 2 \cdot (5-2) = &lt;/math&gt;  :&lt;math&gt; \, = 3 \cdot 2 + 2 \cdot 3 = 6 + 6 = 12 &lt;/math&gt;'</title>
		<link rel="alternate" type="text/html" href="https://minidemo.mathonline.se/index.php?title=1_1.2_L%C3%B6sning_5a&amp;diff=22896&amp;oldid=prev"/>
				<updated>2015-03-21T11:03:57Z</updated>
		
		<summary type="html">&lt;p&gt;Skapade sidan med &amp;#039;:&amp;lt;math&amp;gt; \, 3\,(6-4) + 2\,(5-2) = 3 \cdot (6-4) + 2 \cdot (5-2) = &amp;lt;/math&amp;gt;  :&amp;lt;math&amp;gt; \, = 3 \cdot 2 + 2 \cdot 3 = 6 + 6 = 12 &amp;lt;/math&amp;gt;&amp;#039;&lt;/p&gt;
&lt;p&gt;&lt;b&gt;Ny sida&lt;/b&gt;&lt;/p&gt;&lt;div&gt;:&amp;lt;math&amp;gt; \, 3\,(6-4) + 2\,(5-2) = 3 \cdot (6-4) + 2 \cdot (5-2) = &amp;lt;/math&amp;gt;&lt;br /&gt;
&lt;br /&gt;
:&amp;lt;math&amp;gt; \, = 3 \cdot 2 + 2 \cdot 3 = 6 + 6 = 12 &amp;lt;/math&amp;gt;&lt;/div&gt;</summary>
		<author><name>Taifun</name></author>	</entry>

	</feed>