https://minidemo.mathonline.se/index.php?action=history&feed=atom&title=1.5_L%C3%B6sning_5aa1.5 Lösning 5aa - Versionshistorik2026-04-09T12:17:02ZVersionshistorik för denna sida på wikinMediaWiki 1.23.1https://minidemo.mathonline.se/index.php?title=1.5_L%C3%B6sning_5aa&diff=28258&oldid=prevTaifun: Skapade sidan med '<math>\begin{array}{rclcl} x^3 & = & 27 & \qquad | & \sqrt[3]{\,.\,} \\ \sqrt[3]{x^3} & = & \sqrt[3]{27} & & \\...'2019-01-22T11:01:12Z<p>Skapade sidan med '<math>\begin{array}{rclcl} x^3 & = & 27 & \qquad | & \sqrt[3]{\,.\,} \\ \sqrt[3]{x^3} & = & \sqrt[3]{27} & & \\...'</p>
<p><b>Ny sida</b></p><div><math>\begin{array}{rclcl} x^3 & = & 27 & \qquad | & \sqrt[3]{\,.\,} \\<br />
\sqrt[3]{x^3} & = & \sqrt[3]{27} & & \\<br />
x & = & 3 & & \\<br />
\end{array}</math><br />
<br />
Alternativt<span style="color:black">:</span><br />
<br />
<math>\begin{array}{rclcl} x^3 & = & 27 & \qquad | & (\,\cdot\,)^{1 \over 3} \\<br />
(x^3)^{1 \over 3} & = & 27^{1 \over 3} & & \\<br />
x^{3\cdot{1 \over 3}} & = & 27^{1 \over 3} & & \\<br />
x & = & 3 & & \\<br />
\end{array}</math></div>Taifun