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1.2 Lösning 4a - Versionshistorik
2026-04-07T10:18:41Z
Versionshistorik för denna sida på wikin
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Taifun den 12 december 2010 kl. 17.33
2010-12-12T17:33:25Z
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<td colspan='2' style="background-color: white; color:black; text-align: center;">← Äldre version</td>
<td colspan='2' style="background-color: white; color:black; text-align: center;">Versionen från 12 december 2010 kl. 17.33</td>
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<tr><td class='diff-marker'>−</td><td style="color:black; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #ffe49c; vertical-align: top; white-space: pre-wrap;"><div><math> <del class="diffchange diffchange-inline">5 + 3 </del>\<del class="diffchange diffchange-inline">cdot 8 </del>- <del class="diffchange diffchange-inline">6 = 5 </del>+ <del class="diffchange diffchange-inline">24 - 6 </del>= <del class="diffchange diffchange-inline">29 </del>- <del class="diffchange diffchange-inline">6 </del>= <del class="diffchange diffchange-inline">23</del></math></div></td><td class='diff-marker'>+</td><td style="color:black; font-size: 88%; border-style: solid; border-width: 1px 1px 1px 4px; border-radius: 0.33em; border-color: #a3d3ff; vertical-align: top; white-space: pre-wrap;"><div><math> \<ins class="diffchange diffchange-inline">displaystyle (x</ins>-<ins class="diffchange diffchange-inline">2)^2 </ins>+ <ins class="diffchange diffchange-inline">(x+1)^2 </ins>= <ins class="diffchange diffchange-inline">x^2 </ins>- <ins class="diffchange diffchange-inline">4\,x + 4 + x^2 + 2\,x + 1 </ins>= <ins class="diffchange diffchange-inline">2\,x^2 - 2\,x + 5 </ins></math></div></td></tr>
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Taifun
https://minidemo.mathonline.se/index.php?title=1.2_L%C3%B6sning_4a&diff=61&oldid=prev
Taifun: Created page with "<math> 5 + 3 \cdot 8 - 6 = 5 + 24 - 6 = 29 - 6 = 23</math>"
2010-09-17T11:07:58Z
<p>Created page with "<math> 5 + 3 \cdot 8 - 6 = 5 + 24 - 6 = 29 - 6 = 23</math>"</p>
<p><b>Ny sida</b></p><div><math> 5 + 3 \cdot 8 - 6 = 5 + 24 - 6 = 29 - 6 = 23</math></div>
Taifun